tan4 θ + tan2 θ is equal to
tan4 θ + tan2 θ is equal to
1). \({\sec ^4}{\rm{\theta }} - {\sec ^2}{\rm{\theta }}\)
2). \({\rm{cose}}{{\rm{c}}^4}{\rm{\theta }} - {\sec ^2}{\rm{\theta }}\)
3). \({\rm{cose}}{{\rm{c}}^4}{\rm{\theta }} - {\rm{cose}}{{\rm{c}}^2}{\rm{\theta }}\)
4). \({\sec ^4}{\rm{\theta \;}} + {\rm{\;}}{\sec ^2}{\rm{\theta }}\)
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⇒ tan4 θ + tan2 θ = tan2 θ (tan2 θ + 1) = (sec2 θ - 1) (tan2 θ + 1) [since, tan2 θ = sec2 θ - 1]
⇒ (sec
2θ - 1) sec
2 θ = $({\sec ^4}{\rm{\theta }} - {\sec ^2}{\rm{\theta }})$
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