What are the roots of the quadratic equation: x2 + 3x - 154 = 0
x2 + 3x - 154 = 0
⇒ x2 + 14x – 11x – 154 = 0
⇒ x(x + 14) – 11(x + 14) = 0
⇒ (x + 14)(x – 11) = 0
Then, x = -14 or x = +11.2. if \(x + \frac{1}{x} = 1\), then the value of \(\frac{{{x^2} + 3x + 1}}{{{x^2} + 7x + 1}}\) is
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