In the following question, two equations are given. You have to solve both the equations and find the relation between ‘x’ and ‘y’ and mark the correct answer.
A. x2 – 10x + 25 = 0
B. y2 = 25
First equation:
x2 – 10x + 25 = 0
⇒ x2 – 5x – 5x + 25 = 0
⇒ x(x – 5) – 5(x – 5)
⇒ x = 5
Second equation:
y2 = 25
⇒ y = -5 or 5
⇒ When x = 5, x = y or x > y
∴ x ≥ y1. Find the number of solution(s) of a pair of linear equation 5x – 7y + 28 = 0 and 10x + 14y – 28 = 0.
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3. If $x^{2}$-3x+1=0, then the value of x+$\frac{1}{x}$
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6. The sum of $6xy(2x - 4z) , 3yz(2x - 3z) and 4xz(3y - 2y^{2})$ is
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