There are two alloys of copper and aluminium, alloy A has 40% aluminium and alloy B has 10% copper. In what ratio should these alloys be mixed so that the cost of total copper becomes equal to the cost of total aluminium in the mixture? (The cost price of aluminium is Rs. 200 per kg and cost price of copper is Rs. 500 per kg)
1). 11 ∶ 24
2). 13 ∶ 22
3). 21 ∶ 11
4). 16 ∶ 19
Suppose ‘x’ kg of alloy A and ‘y’ kg of alloy B is mixed;
∴ Amount of copper in new mixture = (0.6x + 0.1y) kg
Amount of aluminium in new mixture = (0.4x + 0.9y) kg
Since cost price of aluminium is Rs. 200 per kg and cost price of copper is Rs. 500 per kg;
∴ (0.6x + 0.1y) × 500 = (0.4x + 0.9y) × 200
⇒ 300x + 50y = 80x + 180y
⇒ 220x = 130y
⇒ x ? y = 13 ? 22