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In the following question, two equations are given. You have to solve both the equations and find the relation between ‘x’ and ‘y’ and mark the correct answer. A. x2 – 36x + 324 = 0 B. y2 – 42y + 441 = 0

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In the following question, two equations are given. You have to solve both the equations and find the relation between ‘x’ and ‘y’ and mark the correct answer.

A. x2 – 36x + 324 = 0

B. y2 – 42y + 441 = 0


1). if x > y
2). if x ≥ y
3). if x < y
4). if x ≤ y


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1 answers

36 vote
Answered by on | Votes 36 |

First Equation:

x2 – 36x + 324 = 0

⇒ x2 – 18x – 18x + 324 = 0

⇒ x(x – 18) – 18(x – 18) = 0

⇒ x = 18, 18

Second Equation:

y2 – 42x + 441 = 0

⇒ y2 – 21y – 21y + 441 = 0

⇒ y(y – 21) – 21(y – 21) = 0

⇒ y = 21

⇒ x = 18, y = 21

∴ y > x
Accepted Answer

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