In a mixture of 225 liters, the ratio of acid to water is 4 ∶ 1. Another 35 liters of water is added to the mixture. The ratio of acid to water in the new mixture is:
1). 5 : 9
2). 9 : 5
3). 3 : 9
4). 4 : 9
Total mixture = 225 liters
Acid in mixture = $(225\times \frac{4}{5} = 180\;liters)$
Water in mixture = $(225\times \frac{1}{5} = 45\;liters)$
Water added = 35 liters
New ratio = $(\frac{{180}}{{45 + 35\;}} = \;\frac{{180}}{{80}} = \;\frac{9}{4})$
∴ The ratio of acid to water in the new mixture is 9 ? 4