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Of the four numbers whose average is 91, the first is 3/10 times the sum of other three. The first number is :

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Of the four numbers whose average is 91, the first is 3/10 times the sum of other three. The first number is :
1). 126
2). 56
3). 168
4). 84


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Answered by on | Votes 2 |

Let the first number be x.

x = (3/10) × (sum of other three sides)

Therefore, sum of other three sides = (10/3) × x

Average = Sum of four sides/4

Average = (x + sum of other three sides)/4

Therefore, Average = (x + 10x/3)/4

Since average = 91

91 = (13x/3)/4

x = (91 × 12)/13

x = 84

Therefore, the first number is 84.

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