An amount of Rs 1,00,000 is invested in two types of shares. The first yields an interest of 9% p.a. and the second, 11% p.a. If the total interest at the end of one year is \(9\frac{3}{4}\%\), then the amount invested in each share was:
1). Rs. 52,500; Rs. 47,500
2). Rs. 62,500; Rs. 37,500
3). Rs. 72,500; Rs. 27,500
4). Rs. 82,500; Rs. 17,500
Let x be the amount invested at 9% and (1,00,000 - x) be invested at 11%
According to the given condition,
$(\Rightarrow \frac{{x \times 1 \times 9}}{{100}} + \frac{{\left( {1,00,000 - x} \right) \times 1 \times 11}}{{100}} = \frac{{1,00,000 \times 1 \times 9.75}}{{100}})$
∴ 9x + 11,00,000 - 11x = 9,75,000
∴ 2x = 1,25,000
∴ x = 62,500
∴ The amount invested in each share is Rs. 62,500 and Rs. 37,500