If f(2, 7) = 57 and f(1, 6) = 37, what is the value of f(3, 10)?
1). 94
2). 20
3). 127
4). 157
The function f(a, b) = a3 + b2
⇒ f(2, 7) therefore is = 23 + 72
⇒ 8 + 49 = 57
⇒ f(1, 6) = 13 + 62
⇒ 1 + 36 = 37
⇒ f(3, 10) = 33 + 102 = 27 + 100 = 127
∴ The value is 1271. Common factor of $24b^{6}c^{8}d^{2}$ , $18a^{6}c^{2}d^{4}$, 12$a^{4}b^{4}$ is
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