In the following question two equations are given. You have to solve these equations and determine relation between a and b.
I. a2 - a - 156 = 0
II. b2 - b - 210 = 0I. a2 - a - 156 = 0
⇒ a2 - 13a + 12a - 156 = 0
⇒ a(a - 13) + 12(a - 13) = 0
⇒ (a - 13)(a + 12) = 0
Then, a = 13 or a = -12
II. b2 - b - 210 = 0
⇒ b2 –15b + 14 + 210 = 0
⇒ b(b - 15) + 14(b - 15) = 0
⇒ (b - 15)(b + 14) = 0
Then, b = 15 or b = -14
So, when a = 13, a < b for b = 15 and a > b for b = -14
And when a = -12, a < b for b = 15 and a > b for b = -14
∴ We can observe that a = b or the relationship cannot be determined.