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In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer I. x2 - 36 = 0 II. 3y2-26y + 35 = 0

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In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer

I. x2 - 36 = 0

II. 3y2-26y + 35 = 0


1). if x > y
2). if x ≥ y
3). if x < y
4). if x ≤ y


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Answered by on | Votes 1 |

I. x2$ - 36 = 0

⇒ x2$ = 36

⇒ x = ±6

II. 3y2$-26y + 35 = 0

⇒ 3y2 $-21y - 5y + 35 = 0

⇒ 3y(y - 7) - 5(y - 7) = 0

⇒ (y - 7)(3y - 5) = 0

⇒ y = 7 or 5/3

When, x = 6, x < y for y = 7 and x > y for y = 5/3

And when, x = -6, x < y for y = 7 and x < y for y = 5/3

∴ no relation can be established between x and y.

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