In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer
I. x2 - 36 = 0
II. 3y2-26y + 35 = 0
I. x2$ - 36 = 0
⇒ x2$ = 36
⇒ x = ±6
II. 3y2$-26y + 35 = 0
⇒ 3y2 $-21y - 5y + 35 = 0
⇒ 3y(y - 7) - 5(y - 7) = 0
⇒ (y - 7)(3y - 5) = 0
⇒ y = 7 or 5/3
When, x = 6, x < y for y = 7 and x > y for y = 5/3
And when, x = -6, x < y for y = 7 and x < y for y = 5/3
∴ no relation can be established between x and y.