Directions: There are 4 jars A, B, C and D having mixture of milk and water in it. Ratio of milk and water in these mixtures are 7 ∶ 13, 4 ∶ 1, 1 ∶ 3 and 11 ∶ 9.
If the quantity of water in jar C was 21.6 litres more than the quantity of milk in jar D and sum of quantity of milk in jar C and the quantity of water in jar D is 189.6 litres, then find the quantity of water that should be mixed in jar D to get a new mixture having 36% milk.
Percentage of milk in these mixtures will be 35%, 80%, 25% and 55%.
Percentage of milk in jar C and D are 25% and 55% and that of water are 75% and 45%;
Let total quantities in two jars be C and D;
According to the question;
0.75C – 0.55D = 21.6
0.25C + 0.45D = 189.6
Solving both the equations;
C = 240 litres and D = 288 litres
Let z litres water is mixed in jar D to get a new mixture containing 36% milk and 64% water;
∴ 288 × 0.45 + z = (288 + z) × 0.64
⇒ 0.36z = 288 × 0.19
⇒ 0.36z = 54.72
⇒ z = 152 litres
∴ 152 litres water should be mixed in jar D to get a new mixture containing 36% milk
1. National Education Day is observed on which of the following day?