Six times the weight of A is 30 kg less than 5 times the weight of B. If B is 17 kg heavier than A, find the sum of their weights.
1). 127 kg
2). 137 kg
3). 147 kg
4). 157 kg
Let the weights of A and B be ‘x’ kg and ‘y’ kg respectively
Given, six times the weight of A is 30 kg less than 5 times the weight of B
⇒ 6x = 5y – 30 ----(1)
Also, B is 17 kg heavier than A,
⇒ y = x + 17 ----(2)
Substituting (2) in (1), we get,
⇒ 6x = 5(x + 17) – 30
⇒ 6x – 5x = 85 – 30
⇒ x = 55 kg
Substituting in (2),
⇒ y = 55 + 17 = 72 kg
∴ Sum of their weights = x + y = 55 + 72 = 127 kg3. Evaluate using identities: (10a + 5b)(100a – 50b)
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