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If x, y and z are real numbers such that (x - 4)2 + (y - 5)2 + (z - 6)2 = 0 then (x + y + z) is equal to

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If x, y and z are real numbers such that (x - 4)2 + (y - 5)2 + (z - 6)2 = 0 then (x + y + z) is equal to
1). -15
2). 3
3). 7
4). 15


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1 answers

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Answered by on | Votes 0 |

We know that if the sum of squares of real numbers = 0 then each number is individually 0.

Here given that, (x - 4)2 + (y - 5)2 + (z - 6)2 = 0

From above information we can say,

x – 4 = 0 ⇒ x = 4;

y – 5 = 0 ⇒ y = 5;

z – 6 = 0 ⇒ z = 6;

∴ (x + y + z) = (4 + 5+ 6) = 15

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