A bus moves at a speed of 84 km/hr after repairing and moves at a speed of 56 km/hr before repairing. It covers 2x distance in 8 hours after repairing. How much time (in hours) will ittake to cover x distance before repairing?
Let Speed of Bus after repairing is SA = 84 km/hr and speed before repairing is SB = 56km/hr.
SA = Distance/Time
⇒ 84 = 2X/8
⇒ X = 84 × 4 = 336 km
SB = Distance/Time = X/Time
⇒ 56 = 336/Time
∴ Time = 336/56 = 6 hours