A trapezium of area 55 cm2 can be divided into a rectangle and two equal triangles. If the parallel sides of the trapezium are of 15 cm and 7 cm, find the area of the triangle.
1). 10 cm2
2). 20 cm2
3). 25 cm2
4). 35 cm2
Area of trapezium = (height of trapezium × sum of parallel sides)/2
⇒ Height of trapezium = (55 × 2)/(15 + 7) = 110/22 = 5 cm
Now,
Area of the triangles = area of trapezium – area of rectangle = 55 – (5 × 7) = 55 – 35 = 20 cm2
As the two triangles are equal, area of one triangle = 20/2 = 10 cm2