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Question 1:Determine whether or not each of the definition of given below gives a binary operation. In the event that * is not a binary operation, give justification for this.(i) On Z , define * by a * b = a − b(ii) On Z , define * by a * b = ab(iii) On R, define * by a * b = ab2(iv) On Z , define...

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Question 1:

Determine whether or not each of the definition of given below gives a binary operation. In the event that * is not a binary operation, give justification for this.

(i) On Z , define * by a * b = a b

(ii) On Z , define * by a * b = ab

(iii) On R, define * by a * b = ab2

(iv) On Z , define * by a * b = |a b|

(v) On Z , define * by a * b = a


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Answer:

(i) On Z , * is defined by a * b = a − b.

It is not a binary operation as the image of (1, 2) under * is 1 * 2 = 1 − 2 = −1 ∉ Z .

(ii) On Z , * is defined by a * b = ab.

It is seen that for each a, bZ , there is a unique element ab in Z .

This means that * carries each pair (a, b) to a unique element a * b = ab in Z .

Therefore, * is a binary operation.

(iii) On R, * is defined by a * b = ab2.

It is seen that for each a, bR, there is a unique element ab2 in R.

This means that * carries each pair (a, b) to a unique element a * b = ab2 in R.

Therefore, * is a binary operation.

(iv) On Z , * is defined by a * b = |a − b|.

It is seen that for each a, bZ , there is a unique element |a − b| in Z .

This means that * carries each pair (a, b) to a unique element a * b = |a − b| in Z .

Therefore, * is a binary operation.

(v) On Z , * is defined by a * b = a.

* carries each pair (a, b) to a unique element a * b = a in Z .

Therefore, * is a binary operation.

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