Answer:

Sc			3
Ti	1	2	3	4
V	1	2	3	4	5
Cr	1	2	3	4	5	6
Mn	1	2	3	4	5	6	7
Fe	1	2	3	4	5	6
Co	1	2	3	4	5
Ni	1	2	3	4
Cu	1	2	3
Zn		2

From the above table, it is evident that the maximum number of oxidation states is shown by Mn, varying from 2 to 7. The number of oxidation states increases on moving from Sc to Mn. On moving from Mn to Zn, the number of oxidation states decreases due to a decrease in the number of available unpaired electrons. The relative stability of the 2 oxidation state increases on moving from top to bottom. This is because on moving from top to bottom, it becomes more and more difficult to remove the third electron from the d-orbital.