Question 4.9:The activation energy for the reaction2HI(g) → H2 I2(g)is 209.5 kJ mol−1 at 581K. Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy?
Question 4.9:
The activation energy for the reaction
2HI(g) → H2 I2(g)
is 209.5 kJ mol−1 at 581K. Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy?
1 answers
Answer:
In the given case:
Ea = 209.5 kJ mol−1 = 209500 J mol−1
T = 581 K
R = 8.314 JK−1 mol−1
Now, the fraction of molecules of reactants having energy equal to or greater than activation energy is given as:
x=e-Ea/RT⇒In
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