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Question 1.22:If the speed of light is 3.0 ×108 m s-1, calculate the distance covered by light in 2.00 ns.
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Question 1.22:
If the speed of light is 3.0 ×108 m s-1, calculate the distance covered by light in 2.00 ns.
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Answer:
According to the question:
Time taken to cover the distance = 2.00 ns
= 2.00 × 10–9 s
Speed of light = 3.0 × 108 ms–1
Distance travelled by light in 2.00 ns
= Speed of light × Time taken
= (3.0 × 108 ms –1) (2.00 × 10–9 s)
= 6.00 × 10–1 m
= 0.600 m
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