Question 6.20:The equilibrium constant for a reaction is 10. What will be the value of ΔGθ? R = 8.314 JK–1 mol–1, T = 300 K.

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Question 6.20:The equilibrium constant for a reaction is 10. What will be the value of ΔGθ? R = 8.314 JK–1 mol–1, T = 300 K.

Asked on 2021-01-23 23:04:10 by Guest | Votes 0 | Views: 25 | Tags: 11th class | chemistry | chapter 6 chemical thermodynamics | Add Bounty

Question 6.20:

The equilibrium constant for a reaction is 10. What will be the value of ΔG^θ? R = 8.314 JK^–1 mol^–1, T = 300 K.

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Answered by Guest on 2021-01-23 23:05:55 | Votes 0 | #

Answer:

From the expression,

ΔG^θ = –2.303 RT logK_eq

ΔG^θ for the reaction,

= (2.303) (8.314 JK^–1 mol^–1) (300 K) log10

= –5744.14 Jmol^–1

= –5.744 kJ mol^–1

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