In a family there are several brothers and sisters. Every 2 boys have brothers as many as sisters and each girl has 2 brothers less than twice as many brothers as sisters. Now find the number of boys and girls.

Asked on 2021-05-29 23:39:56 by Guest | Votes 0 | Views: 931 | Tags: reasoning | puzzle

In a family there are several brothers and sisters. Every 2 boys have brothers as many as sisters and each girl has 2 brothers less than twice as many brothers as sisters. Now find the number of boys and girls.

A). 8 , 6

B). 6 , 8

C). 6 , 8

D). 12 , 10

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Guest · Answer 1 · 2021-05-30 11:27:58

8 , 6

Let B be the number of brothers and S be the number of sisters in the family.
Consider any two boys. They would be having (B - 2) brothers (excluding the two). But this number is equal to the number of sisters they have.
Therefore,
B - 2 = S
or , B - S = 2 ............(1) Each girl will have (S - 1) sisters. Twice the number of sisters = 2(S - 1).
Since, each girl has twice as many brothers as sisters, we have, 2(S-1)-2 = B
2S - 4 = B ........... (2)

Substituting, eqn (2) in Eqn (1), we get
2S - 4 - S = 2
S = 6
On substituting S = 6 in eqn (1) , we get
B - 6 = 2
B = 8.

In a family there are several brothers and sisters. Every 2 boys have brothers as many as sisters and each girl has 2 brothers less than twice as many brothers as sisters. Now find the number of boys and girls.

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