A body of 4.0 kg is lying at rest. Under the action of a constant force, it gains a speed of 5 m/s. The work done by the force will be ________
A). 50 J
B). 30 J
C). 20 J
D). 40 J
50 J
Work done = 1/2*m*V2
=1/2*4*52
= 1/2*4*25
= 2*25
= 50 J
2. ______ is the perpendicular distance between point of application of force and axis of rotation.
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7. The different colours of different stars are due to the variation of