Determine Output:void main(){ static int i=5; if(--i){ main(); printf("%d ", i); }}
Determine Output:void main(){ static int i=5; if(--i){ main(); printf("%d ", i); }}
A). 5 4 3 2 1
B). 0 0 0 0
C). Infinite Loop
D). None of These
1 answers
0 0 0 0
The variable "i" is declared as static, hence memory for I will be allocated for only once, as it encounters the statement. The function main() will be called recursively unless I becomes equal to 0, and since main() is recursively called, so the value of static I ie., 0 will be printed every time the control is returned.
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