If x = $2+ \sqrt{3}$ , then what is the value of $\sqrt{2x} +\frac{1}{\sqrt{2x}}$ ?

If x = $2+ \sqrt{3}$ , then what is the value of $\sqrt{2x} +\frac{1}{\sqrt{2x}}$ ?
1). $2\sqrt{3}$
2). $3\sqrt{3}$
3). $\frac{(3\sqrt{3} 1)}{2}$
4). $2\sqrt{3} 1$

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Guest · Answer 1 · 2018-01-26 19:13:25

3 vote

Answered by Guest on 2018-01-26 19:13:25 | Votes 3 | #

Its very simple question $3\sqrt{3}$ is the correct answer.

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Guest · Answer 2 · 2018-12-22 21:18:43

0 vote

Answered by Guest on 2018-12-22 21:18:43 | Votes 0 | #

Option 3

Guest · Answer 3 · 2018-12-22 21:18:39

3 vote

Answered by Guest on 2018-12-22 21:18:39 | Votes 3 | #

3√3+1/2

Guest · Answer 4 · 2019-04-26 20:12:44

1 vote

Answered by Guest on 2019-04-26 20:12:44 | Votes 1 | #

2x=4+2rt3 =rt3sqr+rt1sqr +2*rt3*rt1 =sqr(rt3 +rt1) Rt(2x)=rt3+rt1 1/rt(2x)=rt3-rt1 Sum =2rt3

If x = $2+ \sqrt{3}$ , then what is the value of $\sqrt{2x} +\frac{1}{\sqrt{2x}}$ ?

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