In $ \triangle PQR $, $\angle R$= $54^{0}$, the perpendicular bisector of PQ at S meets QR at T. If $\angle TPR$ = $46^{0}$, then what is the value (in degrees) of $\angle PQR$?
In $ \triangle PQR $, $\angle R$= $54^{0}$, the perpendicular bisector of PQ at S meets QR at T. If $\angle TPR$ = $46^{0}$, then what is the value (in degrees) of $\angle PQR$? 1). 25 2). 40 3). 50 4). 60
2 answers
Answered by
Guest on
2018-01-26 19:14:29 | Votes
2 |
#
40 : - is correct hence option 2
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Answered by
Gopal on
2018-05-20 10:12:17 | Votes
3 |
#
Pts ~=qts
So angle p=angle q=x
Ptr is external angle .. so 2x
2x= 80 (angle sum property)
X=40°
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