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In $ \triangle PQR $, $\angle R$= $54^{0}$, the perpendicular bisector of PQ at S meets QR at T. If $\angle TPR$ = $46^{0}$, then what is the value (in degrees) of $\angle PQR$?

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In $ \triangle PQR $, $\angle R$= $54^{0}$, the perpendicular bisector of PQ at S meets QR at T. If $\angle TPR$ = $46^{0}$, then what is the value (in degrees) of $\angle PQR$?
1). 25
2). 40
3). 50
4). 60


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2 answers

2 vote
Answered by on | Votes 2 |
40 : - is correct hence option 2

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3 vote
Answered by on | Votes 3 |
Pts ~=qts So angle p=angle q=x Ptr is external angle .. so 2x 2x= 80 (angle sum property) X=40°




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