Three bottles of equal capacity containing mixture of milk and water in ratio 2 : 5, 3 : 4 and 4 : 5 respectively. These three bottles are emptied into a large bottle. What will be the ratio of milk and water respectively in the large bottle?
1). 73:106
2). 73:116
3). 73:113
4). 73:189
Let the capacity of each bottle = $63$ litres [L.C.M.($7,7,9$)]
Ratio of milk and water in the three bottles respectively = $2:5 , 3:4$ and $4:5$
Milk in 1st bottle = $\frac{2}{(2+5)}\times63=18$ litres
and water in 1st bottle = $63-18=45$ litres
Similarly, milk in 2nd bottle = $\frac{3}{7}\times63=27$ litres
and water in 2nd bottle = $63-27=36$ litres
Similarly, milk in 3rd bottle = $28$ litres and water = $35$ litres
Total milk = $18+27+28=73$ litres
and total water = $45+36+35=116$ litres
$\therefore$ Required ratio = $\frac{73}{116}$
Ans - (B)