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28 vote

An electric iron of 750 W is used for S hours per day. Then the energy consumed in one day by the iron is:

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An electric iron of 750 W is used for S hours per day. Then the energy consumed in one day by the iron is:

A).  6 units

B).  600 units

C).  0.6 units

D).  60 units


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2 answers

0 vote
Answered by on | Votes 0 | | Last Updated: 2021-09-05 08:53:50

 6 units

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26 vote
Answered by on | Votes 26 | | Last Updated: 2021-09-05 08:53:08

Solution: 

Given: Power = 750 W and Time = 8 hours 

Total energy consumed = Power × Time 

Total energy consumed = 750W × 8H = 6000WH (Watt Hour)

We know that 1KW = 1000W

So, Total energy consumed = 6 KWH (Kilo Watt Hour)

1 unit = 1 KWH 

So, Total energy consumed = 6 units 

Answer : A). 6 units




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