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31 vote

If the arithmetic mean of 3a and 4b is greater than 50, and a is twice b,then the smallest possible integer value of a is

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If the arithmetic mean of 3a and 4b is greater than 50, and a is twice b,then the smallest possible integer value of a is
1). 20
2). 18
3). 21
4). 19

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2 answers

19 vote
Answered by on | Votes 19 |
Hello, 18 is correct

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29 vote
Answered by on | Votes 29 |
According to the question, (3a+4b)/2 > 50 3a + 4b > 100 3a + 2a > 100 (given that a = 2b) 5a > 100 a > 20 Hence, smallest possible integer value of a = 21
Accepted Answer




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