Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even ?
A). 1/2
B). 3/4
C). 5/7
D). 11/13
3/4
Total number of cases = 6*6 = 36
Favourable cases = [(1,2),(1,4),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,2),(3,4),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,2),(5,4),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)] = 27
So Probability = 27/36 = 3/4
4. In which approach to probability the outcomes are equally likely to occur?