A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
A). 6 days
B). 12 days
C). 5 days
D). 9 days
6 days
B's 10 day's work = ( 1/15 x 10 ) = 2/3 .
Remaining work = ( 1 - 2/3 ) = 1/3 .
Now, 1/18 work is done by A in 1 day.
Therefore 1/3 work is done by A in ( 18 x 1/3 ) = 6 days.