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The 5th and 9th term of an arithmetic progression are 7 and 13 respectively. What is the 15th term?

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The 5th and 9th term of an arithmetic progression are 7 and 13 respectively. What is the 15th term?
1). 22
2). 21
3). 55
4). 59


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2 answers

2 vote
Answered by on | Votes 2 |
option 1 : - 22

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1 vote
Answered by on | Votes 1 |
T5=7 T9=13 T15=? Tn=[a+(n-1)d] T5=a+4d=7 T9=a+8d=13 a+4d=7 a+8d=13 (subtract) ------------- -4d=-6 d=3/2 a+4 (3/2)=7 a+6=7 a=1 T15=1+(15-1)3/2 T15=1+14 (3/2) =1+21 =22




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