How many numbers of five digits can be formed with the digits 0, 1, 2, 3, 4, 6 and 8?
A). 2120
B). 2140
C). 2160
D). 2180
The first digit can be $1,2,3,4,6,8$ excluding $0$ therefore there is $6$ possibility
balance $4$ digits can be anything that is mentioned in question
$6 \times ^6P_4$
$6 \times 360$
$2160$