In $\triangle ABC$. $\angle A$ =$90^{0}$. BP and CQ are two medians. Then the value of $\frac{BP^{2}+ CQ^{2}}{BC^{2}}$ is

In $\triangle ABC$. $\angle A$ =$90^{0}$. BP and CQ are two medians. Then the value of $\frac{BP^{2}+ CQ^{2}}{BC^{2}}$ is
1). $\frac{4}{5}$
2). $\frac{5}{4}$
3). $\frac{3}{4}$
4). $\frac{3}{5}$

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