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In $\triangle ABC$, D and E are two mid points of sides AB and AC respectively. If $\angle BAC$ = $40^{0}$ and $\angle ABC$ = $65^{0}$ then $\angle CED$ is :

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In $\triangle ABC$, D and E are two mid points of sides AB and AC respectively. If $\angle BAC$ = $40^{0}$ and $\angle ABC$ = $65^{0}$ then $\angle CED$ is :
1). $130^{0}$
2). $75^{0}$
3). $125^{0}$
4). $105^{0}$

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1 vote
Answered by on | Votes 1 |
right answer for this question is option 4

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