In $\triangle ABC$, D and E are points on AB and AC respectively such that $DE\parallel BC$ and DE divides the $\triangle ABC$ into two parts of equal areas. Then ratio of AD and BD is

In $\triangle ABC$, D and E are points on AB and AC respectively such that $DE\parallel BC$ and DE divides the $\triangle ABC$ into two parts of equal areas. Then ratio of AD and BD is
1). 1:1
2). 1:$\sqrt{2}-1$
3). 1:$\sqrt{2}$
4). 1:$\sqrt{2}+1$

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