PQRST is a cyclic pentagon and PT is a diameter, then $\angle PQR + \angle RST$ iS equal to

PQRST is a cyclic pentagon and PT is a diameter, then $\angle PQR + \angle RST$ iS equal to
1). $180^{0}$
2). $270^{0}$
3). $216^{0}$
4). $144^{0}$

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