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If $x sin60^{0} tan30^{0} - tan45^{0}$ = $cosec60^{0} cot 30^{0} - sec^{2}45^{0}$, then x =

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If $x sin60^{0} tan30^{0} - tan45^{0}$ = $cosec60^{0} cot 30^{0} - sec^{2}45^{0}$, then x =
1). 2
2). -2
3). 6
4). -4

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2 answers

3 vote
Answered by on | Votes 3 |
it from previous year ssc papers, option 1 is the right answer

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0 vote
Answered by on | Votes 0 |

x sin60° tan 30° – tan245°
= cosec 60°. cot30° – sec245°

=> x.$\frac{\sqrt{3}}{2}$.$\frac{1}{\sqrt{3}}$ -1

=> $\frac{x}{2}$ -1 = 2-2 = 0

=> $\frac{x}{2}$ = 1

=> x  = 2 .




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