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If tan x = $sin 45^{0}.cos 45^{0} + sin 30^{0}$ ,then the value of x is

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If tan x = $sin 45^{0}.cos 45^{0} + sin 30^{0}$ ,then the value of x is
1). $30^{0}$
2). $45^{0}$
3). $60^{0}$
4). $90^{0}$

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2 answers

2 vote
Answered by on | Votes 2 |
I have read it somewhere $45^{0}$ is correct

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2 vote
Answered by on | Votes 2 |

tanx = sin45°.cos45°+ sin 30°

= $\frac{1}{(\sqrt{2}}$ . $\frac{1}{(\sqrt{2}}$ +  $\frac{1}{2}$ = 1

$\therefore$ tanx = tan 45° => x = 45° .




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