If $sin(\theta + 18^{0})$ = $cos 60^{0}$ $(0 < \theta < 90^{0})$, then the value of $cos5\theta$ is

If $sin(\theta + 18^{0})$ = $cos 60^{0}$ $(0 < \theta < 90^{0})$, then the value of $cos5\theta$ is
1). $\frac{1}{2}$
2). 0
3). $\frac{1}{\sqrt{2}}$
4). 1

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