If $\sqrt{3}tan\theta$ = $3 sin\theta$, then the value of $( sin^{2}\theta - cos^{2}\theta)$ is
1). 1
2). 3
3). $\frac{1}{3}$
4). None
$\sqrt{3}$ tanq = 3 $sin\theta$
= $\sqrt{3}$ $\frac{sin\theta}{cos\theta}$ = 3 sin$\theta$
= $\sqrt{3}$= 3 cos$\theta$
= sin$\theta$ = $\sqrt{1-cos^{2}\theta}$ = $\sqrt{\frac{2}{3}}$
= $sin^{2}\theta$ - $cos^{2}\theta$ = $(\sqrt{\frac{2}{3}})^{2}$ - $(\sqrt{\frac{1}{3}})^{2}$ = $\frac{1}{3}$ .