$\frac{3+\sqrt{6}}{5\sqrt{3}-2\sqrt{12}-\sqrt{32}+\sqrt{50}}$ is equal to
$\frac{3+\sqrt{6}}{5\sqrt{3}-2\sqrt{12}-\sqrt{32}+\sqrt{50}}$ is equal to
1). 3
2). $\sqrt{3}$
3). $3\sqrt{2}$
4). $2\sqrt{3}$
1 answers
Other Questions
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