$2\sqrt[3]{40}-4\sqrt[3]{320}+3\sqrt[3]{625}-3\sqrt[3]{5}$ is equal to :

$2\sqrt[3]{40}-4\sqrt[3]{320}+3\sqrt[3]{625}-3\sqrt[3]{5}$ is equal to :
1). $-2\sqrt[3]{340}$
2). 0
3). $\sqrt[3]{340}$
4). $\sqrt[3]{660}$

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