If $\sqrt{33}$ = 5.745. then the value of $\sqrt{\frac{3}{11}}$ is approximately

If $\sqrt{33}$ = 5.745. then the value of $\sqrt{\frac{3}{11}}$ is approximately
1). 1
2). 0.5223
3). 6.32
4). 2.035

SSC CGL Books

---

Join Telegram Group

Answer This Question
Name:
Email:
Answer :
Sum of (5+1)
Submit:

Other Questions

1. $\left(\frac{2}{\sqrt{5}+\sqrt{3}}-\frac{3}{\sqrt{6}-\sqrt{3}}+\frac{1}{\sqrt{6}+\sqrt{5}}\right)$ is equal to

2. $\sqrt{1+\sqrt{1+\sqrt{1+.....}}}$

3. $\left[\frac{\sqrt{3}+1}{\sqrt{3}-1}+\frac{\sqrt{2}+1}{\sqrt{2}-1}+\frac{\sqrt{3}-1}{\sqrt{3}+1}+\frac{\sqrt{2}-1}{\sqrt{2}+1}\right]$ is simplified to

4. $8^{\frac{2}{3}}$ is equal to :

5. Thc greatest one of $\sqrt{4}$ ,$\sqrt[3]{4}$,$\sqrt[4]{6}$ and $\sqrt[6]{8}$ is

6. Simplify $\frac{1}{\sqrt{100}-\sqrt{99}}-\frac{1}{\sqrt{99}-\sqrt{98}}+\frac{1}{\sqrt{98}-\sqrt{97}}-\frac{1}{\sqrt{97}-\sqrt{96}}+......+\frac{1}{\sqrt{2}-\sqrt{1}}$

7. $\frac{1}{\sqrt{9}-\sqrt{8}}-\frac{1}{\sqrt{8}-\sqrt{7}}+\frac{1}{\sqrt{7}-\sqrt{6}}-\frac{1}{\sqrt{6}-\sqrt{5}}+\frac{1}{\sqrt{5}-\sqrt{4}}$ is equal to

8. The value of $\frac{1}{\sqrt{(12-\sqrt{140})}}-\frac{1}{\sqrt{(8-\sqrt{60})}}-\frac{2}{\sqrt{10+\sqrt{84}}}$ is

9. Let a = $\frac{1}{2-\sqrt{3}}+\frac{1}{3-\sqrt{8}}+\frac{1}{4-\sqrt{15}}$ , Then we have

10. Given that $\sqrt{3}$ =1.732, then the value of $\frac{3 + \sqrt{6}}{5\sqrt{3}-2\sqrt{12}-\sqrt{32}+\sqrt{50}}$ is :