If $0.42\times 100^{k}$ = 42 , then the value of k is

If $0.42\times 100^{k}$ = 42 , then the value of k is
1). 4
2). 2
3). 1
4). 3

SSC CGL Books

---

Join Telegram Group

Answer This Question
Name:
Email:
Answer :
Sum of (1+5)
Submit:

Other Questions

1. The value of $(3+2\sqrt{2})^{-3}+ (3-2\sqrt{2})^{-3}$ is :

2. If $\sqrt{5329}$ = 73, then the value $\sqrt{5329}+\sqrt{53.29}+\sqrt{0.5329}+\sqrt{0.005329}+\sqrt{0.00005329}$ is :

3. Arranging the following in ascending order $3^{34}$,$2^{51}$,$7^{17}$ , we get

4. Which Is greater $\sqrt[3]{2}$ or $\sqrt{3}$

5. If a= $\frac{\sqrt{5}+1}{\sqrt{5}-1}$ and b = $\frac{\sqrt{5}-1}{\sqrt{5}+1}$ , the value of $\left(\frac{a^{2}+ab+b^{2}}{a^{2}-ab+b^{2}}\right)$ is

6. When $(4 +\sqrt{7})$ is presented in the form of perfect square It will be equal to

7. The value of $\frac{2+\sqrt{3}}{2-\sqrt{3}}+\frac{2-\sqrt{3}}{2+\sqrt{3}}+\frac{\sqrt{3}+1}{\sqrt{3}-1}$ is :

8. $2\sqrt[3]{34}-3\sqrt[3]{4}+\sqrt[3]{500}$ is equal to

9. $\left(\frac{2}{\sqrt{6}+2}+\frac{1}{\sqrt{7}+\sqrt{6}}+\frac{1}{\sqrt{8}-\sqrt{7}}+2-2\sqrt{2}\right)$ is equal to :

10. $\sqrt{30+\sqrt{30+\sqrt{30+.....}}}$ is equal to