If $2^{x}$=$3^{y}$=$6^{z}$ , then $\left(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\right)$ is equal to

If $2^{x}$=$3^{y}$=$6^{z}$ , then $\left(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\right)$ is equal to
1). 0
2). 1
3). $\frac{3}{3}$
4). $-\frac{1}{2}$

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