If $\left(\frac{3}{4}\right)^{3}\left(\frac{4}{3}\right)^{-7}$=\left(\frac{3}{4}\right)^{2x} , then x is :

If $\left(\frac{3}{4}\right)^{3}\left(\frac{4}{3}\right)^{-7}$=\left(\frac{3}{4}\right)^{2x} , then x is :
1). -2
2). 2
3). 5
4). $2\frac{1}{2}$

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