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If $3^{2x-y}$=$3^{x+y}$=$\sqrt{27}$. then the value of $3^{x-y}$ will be

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If $3^{2x-y}$=$3^{x+y}$=$\sqrt{27}$. then the value of $3^{x-y}$ will be
1). 3
2). $\frac{1}{\sqrt{3}}$
3). $\sqrt{3}$
4). $\frac{1}{\sqrt{27}}$

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1 answers

3 vote
Answered by on | Votes 3 |
is $\frac{1}{\sqrt{3}}$ is the correct answer am i right

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