The unit digit in the product $(2467)^{155}\times (341)^{72}$ is

The unit digit in the product $(2467)^{155}\times (341)^{72}$ is
1). 7
2). 3
3). 9
4). 1

SSC CGL Books

---

Join Telegram Group

Answer This Question
Name:
Email:
Answer :
Sum of (4+5)
Submit:

Other Questions

1. $\left[\frac{1}{\sqrt{2}+\sqrt{3}-\sqrt{5}}+\frac{1}{\sqrt{2}-\sqrt{3}-\sqrt{5}}\right]$ in simplified form equals to :

2. If $3^{x+y}$=81 and $81^{x-y}$=3, then the value of x is

3. $\left[\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}-\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}}\right]$ simplifies to

4. The value of $\frac{1}{\sqrt{3.25}+\sqrt{2.25}}+\frac{1}{\sqrt{4.25}+\sqrt{3.25}}+\frac{1}{\sqrt{5.25}+\sqrt{4.25}}+\frac{1}{\sqrt{6.25}+\sqrt{5.25}}$ is :

5. The value of $\frac{1}{1+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+\frac{1}{\sqrt{3}+\sqrt{4}}+\frac{1}{\sqrt{4}+\sqrt{5}}+.........+\frac{1}{\sqrt{8}+\sqrt{9}}$

6. $\frac{1}{\sqrt{3}+\sqrt{4}}+\frac{1}{\sqrt{4}+\sqrt{5}}+\frac{1}{\sqrt{5}+\sqrt{6}}+\frac{1}{\sqrt{6}+\sqrt{7}}+\frac{1}{\sqrt{7}+\sqrt{8}}+\frac{1}{\sqrt{8}+\sqrt{9}}$ is equal to

7. $(125)^{\frac{2}{3}}\times (625)^{-\frac{1}{4}}$=$5^{x}$ , then the value of x is

8. If $\sqrt{3}$ =1.732, then what is the value of $\frac{4+3\sqrt{3}}{\sqrt{7+4\sqrt{3}}}$ upto three places of decimal

9. The approximate value of $\frac{3\sqrt{12}}{2\sqrt{28}}+\frac{2\sqrt{21}}{\sqrt{98}}$ is :

10. The number of prime factors in $6^{333}\times 7^{222}\times 8^{111}$