The largest number of five digits which, when divided by 10, 24, 30, or 36 leaves the same remainder 10 in each case, is :
The largest number of five digits which, when divided by 10, 24, 30, or 36 leaves the same remainder 10 in each case, is :
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2 answers
Answered by
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2018-04-09 19:24:41 | Votes
1 |
# Using Rule 9,
We will find the LCM of 16, 24,
30 and 36
LCM = 2 × 2 × 2 × 3 × 2 × 5
× 3 = 720
The largest number of five digits
= 99999
On dividing 99999 by 720, the
remainder = 639
The largest five-digit number
divisible by 720
= 99999 – 639 = 99360
Required number = 99360 + 10
= 99370
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